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(C)=3C^2-1200+133500
We move all terms to the left:
(C)-(3C^2-1200+133500)=0
We get rid of parentheses
-3C^2+C+1200-133500=0
We add all the numbers together, and all the variables
-3C^2+C-132300=0
a = -3; b = 1; c = -132300;
Δ = b2-4ac
Δ = 12-4·(-3)·(-132300)
Δ = -1587599
Delta is less than zero, so there is no solution for the equation
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